Rs Aggarwal 2020 2021 for Class 7 Maths Chapter 23 - Probability

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Rs Aggarwal 2020 2021 Solutions for Class 7 Maths Chapter 23 Probability are provided here with simple step-by-step explanations. These solutions for Probability are extremely popular among Class 7 students for Maths Probability Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggarwal 2020 2021 Book of Class 7 Maths Chapter 23 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Rs Aggarwal 2020 2021 Solutions. All Rs Aggarwal 2020 2021 Solutions for class Class 7 Maths are prepared by experts and are 100% accurate.

Page No 283:

Answer:

Total number of trials = 300
Number of times a head is obtained = 136
Number of times a tail is obtained= 164

(i) Probability of getting head = $\frac{Numbe r of times heads is obtained}{Total number of trials}$ = $\frac{136}{300} = \frac{34}{75}$

(ii) Probability of getting a tail = $\frac{Number of times tails is obtained}{Total number of trials}$ = $\frac{164}{300} = \frac{41}{75}$

Page No 283:

Answer:

Total number of trials = 200
Number of times 2 heads are obtained = 58
Number of times one head is obtained = 83
Number of times no head is obtained = 59

(i) Probability of getting 2 heads = $\frac{Number of times 2 heads have been obtained}{Total number of trials}$ = $\frac{58}{200} = \frac{29}{100}$

(ii) Probability of getting 1 head = $\frac{Number of times 1 head has been obtained}{Total number of trials}$ = $\frac{83}{200}$

(iii) Probability of getting 0 head = $\frac{Number of times head has not been obtained}{Total number of trials}$ = $\frac{59}{200}$

Page No 283:

Answer:

Total number of trials = 100
Number of times 3 is obtained = 18
Number of times 6 is obtained = 9
Number of times 4 is obtained = 15
Number of times 1 is obtained = 21

$(i) Probability of getting a 3 = \frac{Number of times 3 is obtained}{Total number of trials} = \frac{18}{100} = \frac{9}{50} (ii) Probability of getting a 6 = \frac{Number of times 6 is obtained}{Total number of trials} = \frac{9}{100} (iii) Probability of getting a 4 = \frac{Number of times 4 is obtained}{Total number of trials} = \frac{15}{100} = \frac{3}{20} (iv) Probability of getting a 1 = \frac{Number of times 1 is obtained}{Total number of trials} = \frac{21}{100}$

Page No 283:

Answer:

Total number of ladies surveyed = 100
Ladies who like coffee = 36
Ladies who do not like coffee = 64

$(i) Probability of choosing a lady who likes coffee = \frac{Number of ladies who like coffee}{Total number of ladies} = \frac{36}{100} = \frac{9}{25} (ii) Probability of choosing a lady who dislikes coffee = \frac{Number of ladies who dislike coffee}{Total number of ladies} = \frac{64}{100} = \frac{16}{25}$

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