Page No 20.13:
Question 1:
A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m2?
Answer:
Page No 20.13:
Question 2:
A plot is in the form of a rectangle ABCD having semi-circle on BC as shown in Fig. 20.23. If AB = 60 m and BC = 28 m, find the area of the plot.
Answer:
Page No 20.13:
Question 3:
A playground has the shape of a rectangle, with two semi-circles on its smaller sides as diameters, added to its outside. If the sides of the rectangle are 36 m and 24.5 m, find the area of the playground. (Take π = 22/7).
Answer:
Page No 20.13:
Question 4:
A rectangular piece is 20 m long and 15 m wide. From its four corners, quadrants of radii 3.5 m have been cut. Find the area of the remaining part.
Answer:
Page No 20.14:
Question 5:
The inside perimeter of a running track (shown in Fig. 20.24) is 400 m. The length of each of the straight portion is 90 m and the ends are semi-circles. If track is everywhere 14 m wide, find the area of the track. Also, find the length of the outer running track.
Answer:
Page No 20.14:
Question 6:
Find the area of Fig. 20.25, in square cm, correct to one place of decimal. (Take π = 22/7)
Answer:
Page No 20.14:
Question 7:
The diameter of a wheel of a bus is 90 cm which makes 315 revolutions per minute. Determine its speed in kilometres per hour. [Use π = 22/7]
Answer:
Page No 20.14:
Question 8:
The area of a rhombus is 240 cm2 and one of the diagonal is 16 cm. Find another diagonal.
Answer:
Page No 20.14:
Question 9:
The diagonals of a rhombus are 7.5 cm and 12 cm. Find its area.
Answer:
Page No 20.14:
Question 10:
The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.
Answer:
Page No 20.14:
Question 11:
Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm. If one of its diagonals is 8 cm long, find the length of the other diagonal.
Answer:
Page No 20.14:
Question 12:
The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per m2 is Rs 4.
Answer:
Page No 20.14:
Question 13:
A rectangular grassy plot is 112 m long and 78 m broad. It has a gravel path 2.5 m wide all around it on the side. Find the area of the path and the cost of constructing it at Rs 4.50 per square metre.
Answer:
Page No 20.14:
Question 14:
Find the area of a rhombus, each side of which measures 20 cm and one of whose diagonals is 24 cm.
Answer:
Page No 20.14:
Question 15:
The length of a side of a square field is 4 m. what will be the altitude of the rhombus, if the area of the rhombus is equal to the square field and one of its diagonal is 2 m?
Answer:
Page No 20.14:
Question 16:
Find the area of the field in the form of a rhombus, if the length of each side be 14 cm and the altitude be 16 cm.
Answer:
Page No 20.14:
Question 17:
The cost of fencing a square field at 60 paise per metre is Rs 1200. Find the cost of reaping the field at the rate of 50 paise per 100 sq. metres.
Answer:
Page No 20.14:
Question 18:
In exchange of a square plot one of whose sides is 84 m, a man wants to buy a rectangular plot 144 m long and of the same area as of the square plot. Find the width of the rectangular plot.
Answer:
Page No 20.14:
Question 19:
The area of a rhombus is 84 m2. If its perimeter is 40 m, then find its altitude.
Answer:
Page No 20.14:
Question 20:
A garden is in the form of a rhombus whose side is 30 metres and the corresponding altitude is 16 m. Find the cost of levelling the garden at the rate of Rs 2 per m2.
Answer:
Page No 20.14:
Question 21:
A field in the form of a rhombus has each side of length 64 m and altitude 16 m. What is the side of a square field which has the same area as that of a rhombus?
Answer:
Page No 20.15:
Question 22:
The area of a rhombus is equal to the area of a triangle whose base and the corresponding altitude are 24.8 cm and 16.5 cm respectively. If one of the diagonals of the rhombus is 22 cm, find the length of the other diagonal.
Answer:
Page No 20.22:
Question 1:
Find the area, in square metres, of the trapezium whose bases and altitudes are as under:
(i) bases = 12 dm and 20 dm, altitude = 10 dm
(ii) bases = 28 cm and 3 dm, altitude = 25 cm
(iii) bases = 8 m and 60 dm, altitude = 40 dm
(iv) bases = 150 cm and 30 dm, altitude = 9 dm.
Answer:
Page No 20.22:
Question 2:
Find the area of trapezium with base 15 cm and height 8 cm, if the side parallel to the given base is 9 cm long.
Answer:
Page No 20.22:
Question 3:
Find the area of a trapezium whose parallel sides are of length 16 dm and 22 dm and whose height is 12 dm.
Answer:
Page No 20.22:
Question 4:
Find the height of a trapezium, the sum of the lengths of whose bases (parallel sides) is 60 cm and whose area is 600 cm2.
Answer:
Page No 20.22:
Question 5:
Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm.
Answer:
Page No 20.22:
Question 6:
Find the sum of the lengths of the bases of a trapezium whose area is 4.2 m2 and whose height is 280 cm.
Answer:
Page No 20.22:
Question 7:
Find the area of a trapezium whose parallel sides of lengths 10 cm and 15 cm are at a distance of 6 cm from each other. Calculate this area as
(i) the sum of the areas of two triangles and one rectangle.
(ii) the difference of the area of a rectangle and the sum of the areas of two triangles.
Answer:
Page No 20.22:
Question 8:
The area of a trapezium is 960 cm2. If the parallel sides are 34 cm and 46 cm, find the distance between them.
Answer:
Page No 20.23:
Question 9:
Find the area of Fig. 20.35 as the sum of the areas of two trapezium and a rectangle.
Answer:
Page No 20.23:
Question 10:
Top surface of a table is trapezium in shape. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.
Answer:
Page No 20.23:
Question 11:
The cross-section of a canal is a trapezium in shape. If the canal is 10 m wide at the top 6 m wide at the bottom and the area of cross-section is 72 m2 determine its depth.
Answer:
Page No 20.23:
Question 12:
The area of a trapezium is 91 cm2 and its height is 7 cm. If one of the parallel sides is longer than the other by 8 cm, find the two parallel sides.
Answer:
Page No 20.23:
Question 13:
The area of a trapezium is 384 cm2. Its parallel sides are in the ratio 3 : 5 and the perpendicular distance between them is 12 cm. Find the length of each one of the parallel sides.
Answer:
Page No 20.23:
Question 14:
Mohan wants to buy a trapezium shaped field. Its side along the river is parallel and twice the side along the road. If the area of this field is 10500 m2 and the perpendicular distance between the two parallel sides is 100 m, find the length of the side along the river.
Answer:
Page No 20.24:
Question 15:
The area of a trapezium is 1586 cm2 and the distance between the parallel sides is 26 cm. If one of the parallel sides is 38 cm, find the other.
Answer:
Page No 20.24:
Question 16:
The parallel sides of a trapezium are 25 cm and 13 cm; its nonparallel sides are equal, each being 10 cm, find the area of the trapezium.
Answer:
Page No 20.24:
Question 17:
Find the area of a trapezium whose parallel sides are 25 cm, 13 cm and the other sides are 15 cm each.
Answer:
Page No 20.24:
Question 18:
If the area of a trapezium is 28 cm2 and one of its parallel sides is 6 cm, find the other parallel side if its altitude is 4 cm.
Answer:
Page No 20.24:
Question 19:
In Fig. 20.38, a parallelogram is drawn in a trapezium, the area of the parallelogram is 80 cm2, find the area of the trapezium.
Answer:
Page No 20.24:
Question 20:
Find the area of the field shown in Fig. 20.39 by dividing it into a square, a rectangle and a trapezium.
Answer:
Page No 20.28:
Question 1:
Find the area of the pentagon shown in fig. 20.48, if AD = 10 cm, AG = 8 cm, AH = 6 cm, AF = 5 cm, BF = 5 cm, CG = 7 cm and EH = 3 cm.
Answer:
Page No 20.28:
Question 2:
Find the area enclosed by each of the following figures [Fig. 20.49 (i)-(iii)] as the sum of the areas of a rectangle and a trapezium:
Answer:
Page No 20.28:
Question 3:
There is a pentagonal shaped park as shown in Fig. 20.50. Jyoti and Kavita divided it in two different ways.
Find the area of this park using both ways. Can you suggest some another way of finding its areas?
Answer:
Page No 20.29:
Question 4:
Find the area of the following polygon, if AL = 10 cm, AM = 20 cm, AN = 50 cm, AO = 60 cm and AD = 90 cm.
Answer:
Page No 20.29:
Question 5:
Find the area of the following regular hexagon.
Answer:
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